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2 years ago

True or false: if x=1, then x>0. If false, give a counterexample.

Mathematics

2 answers:

dolphi86 [110]2 years ago

7 0

The aswer is true. If you think bout it 1 is > 0

UkoKoshka [18]2 years ago

3 0

True
because u gotta think about it like that for more then 5 seconds

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When a scatterplot is created from a table of values, which statement is correct?

jeka94

Answer: A is correct option .It is possible for two points to have the same x-coordinate and the same y-coordinate.

Step-by-step explanation:

A scatter plot is a mathematical diagram or 2-dimensional data visualization using Cartesian coordinates to display values for two variables for a set of data by using dots to represent the values occurred for two different variables - one plotted along the x-axis and the other plotted along the y-axis. They show how variables are correlated thats why they are also called correlation plot. For example we have scatter plot with variables as study time and exam grade, so it can happen that 2 students study for same time and got same grade.

Therefore, It is possible for two points to have the same x-coordinate and the same y-coordinate.

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Pick the correct description of the line 2y = 10

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Please help im having problem

jeka94

Answer:

Step-by-step explanation:

Do i need to explain ??????

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2 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

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2 years ago