Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:

Therefore, there 12 possible combinations from these
Answer:
Ok so the original bill you full out is $32.00 in that box. and the next box put 15% of $32
Answer:
PERFECT
YOU GOTTA RIGHT
Step-by-step explanation:
you will have 8 tables so
72 chair / 8 tables = 9 chair per table