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Aleksandr-060686 [28]
3 years ago
13

Which value would make the statement true?

Mathematics
2 answers:
Tanya [424]3 years ago
8 0
Where is the statement?
kkurt [141]3 years ago
4 0

Answer:

Where is the statement mate

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Addison earn $25 Mowing her neighbors lawn. Then she loaned her friend $18, and got $50 from her grandmother for her birthday sh
larisa [96]
$29. 25-18+50=57. 86-57=29
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4 years ago
Tell what shape is created by this cross section.
Viefleur [7K]
Hello!

As you can see this figure is a rectangular prism. Two sides are squares. When the figure is cut facing the squares, the resulting shape will be a square.

I hope this helps!
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3 years ago
Keith wants to triple a recipe for chocolate milk. The original recipe call for 8 oz of milk and 3 teaspoons of chocolate mix. H
jolli1 [7]

Answer: 9 teaspoons

Step-by-step explanation:

To triple the recipe, multiply the amount of chocolate mix by 3.

3 x 3 = 9 teaspoons.

hope this helps

8 0
3 years ago
Todd placed 32 square tiles along the edge of his wooden dining room table, as shown below. Note: Figure is not drawn to scale.
Flauer [41]

Answer:

The diagonal is 421.

Step-by-step explanation:

This is a difficult question. To find the diagonal, you need to find the base and the height of the square. After that, you need to make it a triangle, by using this equation; A=\frac{1}{2} BH (A being area, B being base, and H being height) then find the length of the hypotenuse of the triangle, which I will do for you.

32*13=416 The B and H = 416. Plug it into the equation now;

A=\frac{1}{2}(416*416)\\\\\\A=\frac{1}{2} 173,056\\\\\\A=86,528Now that you have done that, we know that the area of our new triangle is 86,528.

The diagonal is: 421

8 0
3 years ago
Read 2 more answers
If a and b are the roots of the quadratic equation 2r + 6x -7 = 0, form the equation with the following causes.
Pepsi [2]

Answer:

Step-by-step explanation:

Assuming the given equation is actually 2x^2+6x-7=0.

Then \alpha +\beta=-\frac{6}{2} =-3,and,\alpha \beta=-\frac{7}{2}

The sum of roots of the new equation is \frac{1}{2\alpha+1} +\frac{1}{2\beta +1} =\frac{2(\alpha+\beta+1)}{4\alpha \beta+2(\alpha +\beta)+1}

\implies \frac{1}{2\alpha+1} +\frac{1}{2\beta +1} =\frac{2(-3+1)}{4*-3.5+2(-3)+1} =\frac{4}{19}

The product of the roots of the new equation is \frac{1}{2\alpha +1}*\frac{1}{2\beta+1}=\frac{1}{4\alpha \beta+2(\alpha+\beta)+1}

\implies \frac{1}{2\alpha +1}*\frac{1}{2\beta+1}=\frac{1}{4*-3.5+2(-3)+1}   =-\frac{1}{19}

The new equation is given by:

x^2-(sum\:of\:roots)x+product\:of\:roots=0

x^2-\frac{4}{19} x-\frac{1}{19} =0

19x^2-x-1=0

6 0
4 years ago
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