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mr Goodwill [35]
3 years ago
7

Cho hệ các vector

Mathematics
1 answer:
Sav [38]3 years ago
3 0

Answer:

SACAN MÃ QR VÀ NHẬN CÂU TRẢ LỜI

VUI LÒNG ĐƯA TÔI Ở BRAINLIEST

Step-by-step explanation:

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I need help on #11 :)
melomori [17]

Answer:

I think you divide or multiply

7 0
3 years ago
HELP ME PLEASE MY LAST DAY TO TURN THIS IN! MARKING BRAINLIEST
Mariana [72]
Solve the following system by Elimination:
{7 x + 3 y = 22 | (equation 1)
{4 y = 20 | (equation 2)

Divide equation 2 by 4:
{7 x + 3 y = 22 | (equation 1)
{0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 7 | (equation 1)
{0 x+y = 5 | (equation 2)

Divide equation 1 by 7:
{x+0 y = 1 | (equation 1)
{0 x+y = 5 | (equation 2)

Collect results:

Answer: {x = 1, y = 5

_____________________________________________________

Solve the following system:
{y - 2 x = 10 | (equation 1)
{4 x - y = -14 | (equation 2)

Swap equation 1 with equation 2:
{4 x - y = -14 | (equation 1)
{-(2 x) + y = 10 | (equation 2)

Add 1/2 × (equation 1) to equation 2:
{4 x - y = -14 | (equation 1)
{0 x+y/2 = 3 | (equation 2)

Multiply equation 2 by 2:
{4 x - y = -14 | (equation 1)
{0 x+y = 6 | (equation 2)

Add equation 2 to equation 1:
{4 x+0 y = -8 | (equation 1)
{0 x+y = 6 | (equation 2)

Divide equation 1 by 4:
{x+0 y = -2 | (equation 1)
{0 x+y = 6 | (equation 2)

Collect results:

Answer:  {x = -2, y = 6
4 0
3 years ago
3. Seleccione la gráfica correspondiente a la función de la forma Y=mX , encerrando en una circunferencia el literal correcto:
Deffense [45]

Answer:

La respuesta esta abajo

Step-by-step explanation:

La pregunta no está completa porque no contiene gráficos, pero te mostraré cómo responderla.

La ecuación de un gráfico de línea recta viene dada por:

y = mx + b; donde y y x son variables, m es la pendiente de la gráfica y b es la intersección en y (que es el valor de y cuando x es 0)

Dado que la ecuación de la gráfica es y = mx, comparando con la ecuación de una línea recta (y = mx + b), podemos concluir que la gráfica con una ecuación y = mx, tiene una pendiente de my una intersección con y de 0.

Esto significa que la gráfica pasa por el origen sin tocar el eje y. Además, la gráfica tiene una pendiente positiva.

5 0
3 years ago
X^2+y^2 +4x−6y+9=0<br> what is the center and the radius
mojhsa [17]

Answer: Center (-2,3), radius 2

Step-by-step explanation: Subtract 9 from both sides, then complete the square for the x and y variables & add to both sides: x^2+4x+4+y^2-6y+9=-9+4+9 = (x+2)^2+(y-3)^2=4. The center of this circle in the form (x-a)^2+(y-b)^2=r^2 is (a,b) with radius r. a=-2, b=3, r=\sqrt{4}=2

3 0
3 years ago
What is y=1/2(x+3)^2+10 in standard form​
anyanavicka [17]

Answer:

Simplified equation in standard form: y=\frac{1}{4}x^{2}+12\frac{1}{4}

Original equation in standard form: y=1/2(x+3)^2+10

Step-by-step explanation:

y=\frac{1}{2}(x+3)^2+10

<u>Step 1: Distribute the </u>\frac{1}{2}<u> :</u>

<u />y=(\frac{1}{2}*x+\frac{1}{2}*3)^2+10<u />

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

<u />

<u>Step 2: Take </u>(\frac{1}{2}x+1\frac{1}{2})<u> and square it :</u>

<u />y=(\frac{1}{2}x+1\frac{1}{2})^2+10<u />

y=(\frac{1}{2}x)^{2} +(1\frac{1}{2})^2+10

y=(\frac{1}{2}x*\frac{1}{2}x)+(1\frac{1}{2}*1\frac{1}{2})+10

y=\frac{1}{4}x^{2}+2\frac{1}{4}+10

<u />

<u>Step 3: Add the constants:</u>

<u />y=\frac{1}{4}x^{2}+(2\frac{1}{4}+10)<u />

<u />y=\frac{1}{4}x^{2}+(12\frac{1}{4})<u />

<u />

<u>Step 4: Get rid of the parenthesis:</u>

<u />y=\frac{1}{4}x^{2}+12\frac{1}{4}<u />

<u />

<u />

3 0
3 years ago
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