Answer:
D. Computers
Explanation:
Digital art is when you make art on electronic devices.
Answer:
These are the supplies in the list:
[‘pencil’, ‘notebook’, ‘backpack’, ‘pen’, ‘calculator’]
Explanation:
The line return (\n) character will be in the output (so there will be a change of line), but it will NOT be visible as it would have been interpreted as a special character.
So the output will be on 2 different lines, with no \n visible.
If the command would have been: print('These are the supplies in the list:\n', supplies), with single quotes (') instead of double quotes (") then then \n would have been printed but not interpreted as a special character. At least in most computer language. Since we don't know of which language the question refers to, we can't be sure at 100%.
Answer:
True
Explanation:
according to coursehero it's true
Answer:
128 bits
Explanation:
The MD5, which is the acronym for Message-Digest algorithm 5, invented by a professor of MIT, Ronald Rivest, is a cryptographic hash algorithm that creates a 128 bit hash value and is typically represented as a 32 character hex number. MD5 is the improved version of MD4 which was also created by the same professor.
Following is an example format of an MD5 hash;
<em>ef55d3a698d289f2afd663725127bccc</em>
MD5 has been proven to have security issues. One of these issues is called collision attack - a situation where the same hash is produced for different input data.
Answer:
int ComputeFibonacci(int N) {
if(N == 0)
return 0;
else if (N == 1)
return 1;
else
return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);
}
Explanation:
Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.
For example,
If N = 4 as in the main part:
ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3
ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2
ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0 = 1
*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.
