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Tom [10]
2 years ago
14

HELP!! Given the following functions, f(x)=2x²-1 and g(x)=x+3 , find the following and state the domain:

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
8 0

Answer:

jfjufurjfjfjririutkf

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A line intersects the points (6, -12) and (15, -3). What is the slope intercept equation for this line?
Korolek [52]
Let's say that the unknown value here is c. Although we are given two points on the line, it is only necessary to use one as there is only one unknown value, so let's say we choose the point (6, -12) and substitute this into the equation:

-12 = 1(6) - c
-12 - 6 = -c
-18 = -c
c = 18

Thus the equation for the line is y = 1x - 18
8 0
3 years ago
Yessenia is making cookies. the recipe calls for her to use 2/3 cup of white sugar and 1/2 cup of brown sugar. how many cups of
ANTONII [103]

Answer:

7/6

Hope this helps

8 0
2 years ago
Help me with this!!!!
andre [41]

Answer: -93.5

Step-by-step explanation:

Average of the two -94+-93/2= -93.5 so thats the midpoint

4 0
3 years ago
Describe how the graph of y=log (10 000x) is related to the graph of y=log x
Nana76 [90]
Background: log (a . b) = log a + log b 
hence log(10000x) = log 10000 + log x but we know that log 10000 = 4
                               = 4 + log x 
therefore the graph of log(10000x) is just the graph of log x transposed by 4 
5 0
3 years ago
How do I solve part A
seraphim [82]

Answer:

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

Step-by-step explanation:

The procedure for solution of exercise A is described below:

1) We expand the expression.

2) The resulting expression is rearranged into the form of a second order polynomial.

3) Roots are found by Quadratic Formula.

Step 1:

2\cdot x \cdot (x+1.5) = -1

2\cdot (x^{2}+1.5\cdot x) = -1

2\cdot x^{2} + 3\cdot x = -1

Step 2:

2\cdot x^{2}+3\cdot x +1 = 0

Step 3:

x_{1, 2} = \frac{-3\pm \sqrt{3^{2}-4\cdot (2)\cdot (1)}}{2\cdot (2)}

x_{1,2} = -\frac{3}{4}\pm \frac{1}{4}

x_{1,2} = \frac{-3\pm 1}{4}

The solution of this expression is x_{1} = -1 and x_{2} = -\frac{1}{2}.

4 0
3 years ago
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