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DENIUS [597]
2 years ago
11

Which phrase best describes the translation from the graph y = (x â€"" 5)2 7 to the graph of y = (x 1)2 â€"" 2?.

Mathematics
1 answer:
anyanavicka [17]2 years ago
7 0

The vertex of the parabola will move from (5, 7) to (-1, -2).

<h2>Given to us,</h2>

Equation 1, h(x) = (x-5)²+7,

Equation 2, g(x) = (x+1)²-2,

<h2>graph of parabola</h2>

For both the given equations, we will get a graph of parabola(as in the image below),

h(x) = (x-5)²+7, represented in red;

g(x) = (x+1)²-2, represented in blue;

<h3>Coordinates </h3>

Also, we know for a parabola, the coordinates of the vertex of a parabola are given by, f(x) = (x - h)² + k, where (h, k) are coordinates of a vertex of a parabola.

Using the same,

h(x) = (x-5)²+7, coordinates of a vertex of this parabola are (5, 7);

g(x) = (x+1)²-2, coordinates of a vertex of this parabola are (-1, -2);

Therefore, the vertex of the parabola will move from (5, 7) to (-1, -2).

To know more visit:

https://brainly.in/question/11356858

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The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.
7 0
3 years ago
Where are the minimum and maximum values for f(x) = -2 + 4 cos x on the interval (0,21]?
Dafna11 [192]

Answer:

Step-by-step explanation:

Maximum value is when cos x = 1

So it is -2 + 4(1) = 2.

Minimum value, when  cos x = -1:

= -2  + 4(-1) = -6.

4 0
3 years ago
Read 2 more answers
Complete the ordered pair so it a solution of 2x-5y=13
Ilya [14]
2 x - 5y = 13

2 × -1 - 5 × -3 = 13

Answer:
(-1, -3)

6 0
3 years ago
Geometry math question please help
Triss [41]

A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .

In the above given options option A is the right answer.

If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.

Diagonals are perpendicular in a rhombus too.

A square and Rhombus both have diagonals that are perpendicular.

So it is not a necessary condition for a parallelogram to be a square .

The other options are right .

So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.

6 0
3 years ago
If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that
pogonyaev

Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested

Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)

Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)

\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)

Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250

\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250

5 0
3 years ago
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