Question

What is the center and radius of the circle with equation (x - 2)^2 + (y - 5)^2 = 100?

Answer 1

Answer: 
Center = (2,5)
Radius = 10
Choice A

To find this answer, first write the equation 
(x-2)^2 + (y-5)^2 = 100
into 
(x-2)^2 + (y-5)^2 = 10^2

Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2

We see that (h,k) = (2,5) is the center
and r = 10 is the radius

Answer 2

Answer:

A) Center ( 2 , 5 ) ; radius = 10 .

Step-by-step explanation:

Given  :  (x - 2)² + (y - 5)² = 100.

To find : What is the center and radius of the circle with equation.

Solution : We have given  (x - 2)² + (y - 5)² = 100.

Standard form of circle :  (x - h)² + (y - k)² = r².

Where, center = ( h ,k )  , r = radius .

On comparing  (x - 2)² + (y - 5)² = 100 with  (x - h)² + (y - k)² = r².

We can write (x - 2)² + (y - 5)² = 10².

h = 2 , k  = 5 , r = 10 .

Center ( 2 , 5 ) ; radius = 10 .

Therefore, A) Center ( 2 , 5 ) ; radius = 10 .