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qaws [65]
3 years ago
5

The table shows the steps for solving the given inequality for x.

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0
Step                                      justification

- 3 (4 - 6x) < x + 5            

- 12 + 18x < x + 5                 distributive property (to solve the left side)

-12 + 17x < 5                        subtraction property of equality (to transpose x
                                             from right to left side)

                                              subtraction of like terms (18x - x = 17x)

17x < 17                                addition property of equality (to tranpose - 12
                                              from left to right side)

                                              addition of like terms (12 + 5 =17)

x < 1                                      division property of equality



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Answer:

Step-by-step explanation:

(\dfrac{1}{2}a-\dfrac{2}{3}b)(\dfrac{3}{5}a+\dfrac{2}{3}b)=\dfrac{1}{2}a*(\dfrac{3}{5}a+\dfrac{2}{3}b) - \dfrac{2}{3}b*(\dfrac{3}{5}a+\dfrac{2}{3}b) \\\\\\= \dfrac{1}{2}a*\dfrac{3}{5}a  + (\dfrac{1}{2}a*\dfrac{2}{3}b) - \dfrac{2}{3}b*\dfrac{3}{5}a- \dfrac{2}{3}b*\dfrac{2}{3}b\\\\\\=\dfrac{3}{10}a^{2} + \dfrac{1}{3}ab - \dfrac{2}{5}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2} +\dfrac{1*5}{3*5}ab-\dfrac{2*3}{5*3}-\dfrac{4}{9}b^{2}\\\\\\

=\dfrac{3}{10}a^{2}+\dfrac{5}{15}ab-\dfrac{6}{15}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2}-\dfrac{1}{15}-\dfrac{4}{9}b^{2}

8 0
3 years ago
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