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Anit [1.1K]
3 years ago
7

∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 78° and minor arc CD = 124°, what i

s the measure of ∠ABD? A) 23° B) 39° C) 40° Eliminate D) 46°+-

Mathematics
2 answers:
lana [24]3 years ago
4 0
Minor arc AD is 360° -124° -78° = 158°. Then angle ABD is
  (158° -78°)/2 = 40°

The appropriate selection is
  C) 40°

salantis [7]3 years ago
4 0

Answer:

40°

Step-by-step explanation:

First, find minor arc AD.

minor arc AD = 360 - 78 - 124 = 158

then,

∠ABD =

1

2

(minor arc AD - minor arc AC)

∠ABD =

1

2

(158 - 78)

∠ABD =

1

2

80

∠ABD = 40°

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Bart, Lisa, and Maggle are pooling their money to buy a snack from the comer store. Bart has
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Subtract $4.60 from 0.05

Step-by-step explanation:

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3 years ago
The time T required to repair a machine is an exponentially distributed random variable with mean 10 hours.
Firdavs [7]

It can be expected about 36.79% of chance that repair time exceeds

The probability that a repair time exceeds  15 hours is 0.3679

What is the exponential distribution?

It explains about the time between events or the distance between two random events is termed the exponential distribution. Here, the occurrence of the events is continuous and also independent. Moreover, the average rate is constant.

The cumulative distribution function of T is obtained below:

From the information given, let the random variable T be the required time to repair a machine follows exponential distribution with parameter λ
with mean. 1/2 hours

That is,  E(x) =  1/2 hours.
The parameter of the random variable T is,
E(x) =  1/λ
λ = 1/E(x)
= 1/(1/2)
= 2

The probability density function of T is,
f(t) = \left \{ {{2e^{-2t} \ \ \ t > 0}  \  \atop {0} \ \ \ elsewhere} \ \right.
The cumulative density function of T is,
FT(t) = P(T <= t)

= 1 - e^{- \lambda t}

= 1 - e^{- 2t}
The CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
to obtain the probability that a repair time exceeds

1/2 hours.
(a) The probability that a repair time exceeds 1/2 hours.
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise

The required probability is,
P(T <= 1/2)  = 1 - P(T <= 1/2)
        = 1 - [  = 1 - e^{- 2(1/2)} ]
       = e^{-1}
= 0.3679

om total probability. It can be expected about 36.79% of chance that repair time exceeds

P(X => x)  = 1 - P(X < x)
to obtain the probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

(b), The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained below:
From the given information, the CDF of T is,
P(T <= t)  = 1 - e^{- 2t}    0 <= T <= ∞
        = 0          otherwise
The required probability is,
P = P(T => 12.5∩T>12) / P(T>12)
= e^{- 25 + 24}

= e^{- 1}
= 0.3679
The probability that a repair takes at least 12.5 hours given that its duration exceeds 12 hours is obtained by dividing the
P = P(T => 12.5∩T>12) / P(T>12)
with
P(T>12).

It can be expected about 36.79% of chance that a repair takes at least 12.5 hours given that its duration exceeds 12 hours.

Hence, It can be expected about 36.79% of chance that repair time exceeds,

The probability that a repair time exceeds  15 hours is 0.3679

To learn more about the product of the fraction visit,
brainly.com/question/22692312
#SPJ4

7 0
1 year ago
Please help! I will mark brainliest! Random answers will be reported.
pantera1 [17]

Answer:D’ (0, -1)

Step-by-step explanation:

7 0
3 years ago
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brilliants [131]

Answer:

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Step-by-step explanation:

Total cost without the discount = $58 + $7 = $65

Cost of one book = $5

Let the number of books be n

5n = 65

n = 65/5

n = 13

6 0
3 years ago
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