All categories

2 years ago

Write each decimal as a percent. 0.59 0.98 0.02 1.33

Mathematics

2 answers:

Ray Of Light [21]2 years ago

8 0

Answer:

59%

98%

133%

Step-by-step explanation:

0.59 × 100 = 59%

0.98 x 100= 98%

and same with the others

adell [148]2 years ago

6 0

Answer: to find the percent equivalent, multiply the decimal by 100.

59%

98%

133%

hope it helps!

You might be interested in

Help please! Will give brainly

luda_lava [24]

1.) 9 - c < 2 , C = 7
Graph 7 on the number line.
2.) -3c > 15, C = -5
Graph -5 on the number line.
Hope this helps.

4 0

3 years ago

Please help i need answer asap

ycow [4]

Answer:

1: x=-3

2: x=1 is the answer

5 0

2 years ago

What is the value for f(x)4^2x -100 when x=2 ?<br><br> (the ^2x is a exponent)

PolarNik [594]

Answer:

156

Step-by-step explanation:

f(x)= 4^(2x) -100

Let x =2

f(2)= 4^(2*2) -100

= 4^4 - 100

= 256 -100

= 156

3 0

2 years ago

Find the value of g(-1)

Anna11 [10]

Answer:

g(-1) = -3

Step-by-step explanation:

g(-1) is the y value of the graph when x = -1

when x=-1 y=-3

g(-1) = -3

6 0

3 years ago

Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa

Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : $\mu = 15.45$

Standard deviation : $\sigma = 13.70$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x= 5 degrees

$z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76$

For x= 10 degrees

$z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40$

The P-value : $P(-0.76$

$=0.3445783-0.2236273=0.120951\approx0.1210$

In percent , $0.1210\times100=12.10\%$

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0

3 years ago