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Juliette [100K]

2 years ago

7

Please help me! [One Step Inequalities]

1 answer:

IrinaVladis [17]2 years ago

5 0

Answer:

B

Step-by-step explanation:

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The following table shows the length and width of two rectangles:

zhannawk [14.2K]

Answer:

10x - 8 or 2( 5x - 4)

Step-by-step explanation:

Perimeter of a rectangle = 2( Length + Width)

<u>Rectangle A </u>

Length = x + 8,

Width = x - 1

$Perimeter_A = 2((x + 8) + ( x - 1))\\\\$

$= 2(x + 8 + x - 1) \\\\= 2(2x + 7)\\\\=4x + 14$

<u>Rectangle B</u>

Length = 4x + 5

Width = 3x - 2

$Perimeter _B= 2((4x + 5) + (3x-2))\\\\$

$=2(4x + 5 + 3x - 2)\\\\=2(7x + 3)\\\\=14x + 6$

$Perimeter_B - Perimeter_A = (14x +6)-(4x + 14) \\\\$

$=14x + 6 - 4x - 14\\\\=10x -8\\\\or \\\\=2(5x - 4)$

4 0

2 years ago

jamaica class spent 1 3\4 hours in science class. They studied insects for 2\3 of the time. How much time did they spend studyin

viktelen [127]

1 3/4 hours* (2/3)= 1 1/6 hours.

They spent 1 1/6 hours studying insects~

8 0

3 years ago

Read 2 more answers

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

What percent of 287.5 is 46

lozanna [386]

46/287.5 = .16
.16x287.5 = 46

The answer is 16%

3 0

2 years ago

Read 2 more answers

Ian made cookies for a bake sale. He made 91 cookies, including 30 cookies in the shape of a dog.

Yuliya22 [10]

Answer:

total sample space is 91

no of cookies in dog shape is 30

therefore

p(d)=30/91

8 0

2 years ago