Answer:
12,500
Step-by-step explanation:
125%/100% x 10000
12,500
Gonna do a little subbing here...
for 40 pgs of express proof reading....3 bucks per pg...c = 3
40(3) - 0.05(40(3)) = T
120 - 0.05(120) = T.....120 - 6 = T.....114 = T
so express proofreading cost 114
for 40 pgs of basic proof reading....c = 3.95
40(3.95) - 0.05(40(3.95) = T
158 - 0.05(158) = T....158 - 7.9 = T.....150.10
so basic proof reading costs 150.10
for 40 pgs of extended proof reading....c = 5
40(5) - 0.05(40(5) = T
200 - 0.05(200) = T....200 - 10 = 190
so extended proof reading is 190
no need to go further....the extended proof reading is gonna be ur answer...the best quality of editing that keeps it at 190
Answer:
528 square inches
Step-by-step explanation:
SA = 2(10·16) + 2(10·4) +2(4·16)
= 2(160)+2(40)+2(64)
= 320 + 80 + 128
= 528 square inches
Answer:
(2, -3)
Step-by-step explanation:
Apparently, the equations are supposed to be ...
The solution for x can be found by subtracting the second equation from the first:
(4x +y) -(3x +y) = (5) -(3)
x = 2 . . . . . . . matches the second answer choice
Y can be found from either equation:
y = 5 - 4x . . . . . subtract 4x from the first equation
y = 5 -4(2) = -3
The solution is (x, y) = (2, -3).
Answer:
72 feet from the shorter pole
Step-by-step explanation:
The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.
The shorter pole height as a fraction of the total pole height is ...
18/(18+24) = 3/7
so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:
d/168 = 3/7
d = 168·(3/7) = 72
The wire should be anchored 72 feet from the 18 ft pole.
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<em>Comment on the problem</em>
This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.
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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:
L = √(18²+x²) + √(24² +(168-x)²)
and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.