4a + 6b = 10
2a - 4b = 12...multiply by -2
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4a + 6b = 10
-4a + 8b = - 24 (result of multiplying by -2)
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14b = - 14
b = -14/14
b = -1
2a - 4b = 12
2a - 4(-1) = 12
2a + 4 = 12
2a = 12 - 4
2a = 8
a = 8/2
a = 4
so 12a = 12(4) = 48 <==
Answer: she will buy 60 but if she add up all the water bottles togeather it will be 126 but the answer is 60
Step-by-step explanation: so first you have to make 5 boxes on a pice of paper and put 12 lines in each box and you count all the lines in the boxes togeather and they will equal 60 water bottles so the answer is 60
Answer:
3 with a few left over so 4
Step-by-step explanation:
The answer is b. 1/27
3^-3=1/27 and 3^4=81. 1/27×81=3. 3×3=9. 3^-5=1/243. 1/243×9= 1/27. The answer is b. 1/27.
Answer:
$8.00
Step-by-step explanation:
The problem statement gives two relations between the prices of two kinds of tickets. These can be used to write a system of equations for the ticket prices.
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<h3>setup</h3>
Let 'a' and 'c' represent the prices of adult and children's tickets, respectively. The given relations can be expressed as ...
a - c = 1.50 . . . . . . . adult tickets are $1.50 more
175a +325c = 3512.5 . . . . . total revenue from ticket sales.
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<h3>solution</h3>
We are only interested in the price of an adult ticket, so we can eliminate c to give one equation we can solve for 'a'. Using the first equation, an expression for c is ...
c = a -1.50
Substituting that into the second equation, we have ...
175a +325(a -1.50) = 3512.50
500a -487.50 = 3512.50 . . . . . . simplify
500a = 4000 . . . . . . add 487.50
a = 8 . . . . . . . . . divide by 500
An adult ticket costs $8.
