For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points through which the line passes:
![(x_ {1}, y_ {1}) :( 1,3)\\(x_ {2}, y_ {2}): (- 3, -5)](https://tex.z-dn.net/?f=%28x_%20%7B1%7D%2C%20y_%20%7B1%7D%29%20%3A%28%201%2C3%29%5C%5C%28x_%20%7B2%7D%2C%20y_%20%7B2%7D%29%3A%20%28-%203%2C%20-5%29)
We found the slope:
![m = \frac{y_ {2} -y_ {1}} {x_ {2} -x_ {1}}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%20%7B2%7D%20-y_%20%7B1%7D%7D%20%7Bx_%20%7B2%7D%20-x_%20%7B1%7D%7D)
Substituting we have:
![m = \frac {-5-3} {- 3-1} = \frac {-8} {- 4} = 2](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%20%7B-5-3%7D%20%7B-%203-1%7D%20%3D%20%5Cfrac%20%7B-8%7D%20%7B-%204%7D%20%3D%202)
Thus, the equation is of the form:
![y = 2x + b](https://tex.z-dn.net/?f=y%20%3D%202x%20%2B%20b)
We substitute one of the points and find the cut-off point:
![3 = 2 (1) + b\\3 = 2 + b\\3-2 = b\\b = 1](https://tex.z-dn.net/?f=3%20%3D%202%20%281%29%20%2B%20b%5C%5C3%20%3D%202%20%2B%20b%5C%5C3-2%20%3D%20b%5C%5Cb%20%3D%201)
Finally, the equation is:
![y = 2x + 1](https://tex.z-dn.net/?f=y%20%3D%202x%20%2B%201)
ANswer:
![y = 2x + 1](https://tex.z-dn.net/?f=y%20%3D%202x%20%2B%201)
Answer:
2a-3b
Step-by-step explanation:
Answer:
The answer to your question is r = 4 in
Step-by-step explanation:
Data
Volume = 4000 π in³
height = 250 in
radius = ?
Process
1.- Look the formula to calculate the volume of a cylinder
Volume = πr²h
2.- Solve for r²
r² = Volume / πh
3.- Substitution
r² = 4000π / π(250)
4.- Simplification
r² = 16
r = √16
5.- Result
r = 4 in
Given: ![f(x) = \frac{1}{x-2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bx-2%7D)
![g(x) = \frac{2x+1}{x}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Cfrac%7B2x%2B1%7D%7Bx%7D)
A.)Consider
![f(g(x))= f(\frac{2x+1}{x} )](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29)
![f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}](https://tex.z-dn.net/?f=f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29%3D%5Cfrac%7B1%7D%7B%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%29-2%7D)
![f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}](https://tex.z-dn.net/?f=f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B2x%2B1-2x%7D%7Bx%7D%7D)
![f(\frac{2x+1}{x} )=\frac{x}{1}](https://tex.z-dn.net/?f=f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29%3D%5Cfrac%7Bx%7D%7B1%7D)
![f(\frac{2x+1}{x} )=1](https://tex.z-dn.net/?f=f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29%3D1)
Also,
![g(f(x))= g(\frac{1}{x-2} )](https://tex.z-dn.net/?f=g%28f%28x%29%29%3D%20g%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29)
![g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}](https://tex.z-dn.net/?f=g%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29%3D%20%5Cfrac%7B2%28%5Cfrac%7B1%7D%7Bx-2%7D%29%20%2B1%20%7D%7B%5Cfrac%7B1%7D%7Bx-2%7D%7D)
![g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}](https://tex.z-dn.net/?f=g%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29%3D%20%5Cfrac%7B%5Cfrac%7B2%2Bx-2%7D%7Bx-2%7D%20%7D%7B%5Cfrac%7B1%7D%7Bx-2%7D%7D)
![g(\frac{1}{x-2} )= \frac{x }{1}](https://tex.z-dn.net/?f=g%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29%3D%20%5Cfrac%7Bx%20%7D%7B1%7D)
![g(\frac{1}{x-2} )= x](https://tex.z-dn.net/?f=g%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29%3D%20x)
Since, ![f(g(x))=g(f(x))=x](https://tex.z-dn.net/?f=f%28g%28x%29%29%3Dg%28f%28x%29%29%3Dx)
Therefore, both functions are inverses of each other.
B.
For the Composition function ![f(g(x)) = f(\frac{2x+1}{x} )=x](https://tex.z-dn.net/?f=f%28g%28x%29%29%20%3D%20f%28%5Cfrac%7B2x%2B1%7D%7Bx%7D%20%29%3Dx)
Since, the function
is not defined for
.
Therefore, the domain is ![(-\infty,0)\cup(0,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C0%29%5Ccup%280%2C%5Cinfty%29)
For the Composition function ![g(f(x)) =g(\frac{1}{x-2} )=x](https://tex.z-dn.net/?f=g%28f%28x%29%29%20%3Dg%28%5Cfrac%7B1%7D%7Bx-2%7D%20%29%3Dx)
Since, the function
is not defined for
.
Therefore, the domain is ![(-\infty,2)\cup(2,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C2%29%5Ccup%282%2C%5Cinfty%29)
Invisible braces would cost 5300. I think that’s it. Hope that helped