Question

A system of two equations is shown.

Answer 1

Answer:

Please check the explanation.

Step-by-step explanation:

Given the system of equations

2 + 2y = 6

2x - 3y = 26

Let us solve the system of equations

$\begin{bmatrix}2+2y=6\\ 2x-3y=26\end{bmatrix}$

Rearrange equations

$\begin{bmatrix}-3y+2x=26\\ 2y=4\end{bmatrix}$

Multiply -3y+2x=26 by 2:    -6y+4x=52

Multiply 2y = 4 by 3:  6y = 12

$\begin{bmatrix}-6y+4x=52\\ 6y=12\end{bmatrix}$

adding the equations

$6y=12$

$+$

$\underline{-6y+4x=52}$

$4x=64$

Solve 4x = 64 for x

$4x = 64$

divide both sides by 4

$\frac{4x}{4}=\frac{64}{4}$

Simplify

$x = 16$

For -6y+4x = 52 plug in x = 16

$-6y+4\cdot \:16=52$

Multiply the numbers: 4 · 16 = 64

$-6y+64=52$

Subtract 64 from both sides

$-6y+64-64=52-64$

Simplify

$-6y=-12$

Divide both sides by -6

$\frac{-6y}{-6}=\frac{-12}{-6}$

$y=2$

Therefore, the solution to the system of equations be:

$y=2,\:x=16$

Thus,

(x, y) = (16, 2)

Please note that it seems your answer choices have not included the correct option.

Answer 2

Answer:

(10 -2)

Step-by-step explanation:

first you have to substitute the value of x, solve that, substitute the value of y, solve, and that’s about it. :)