Yea I wanna say you have the right answer
I'll write "x" instead theta.
sin x + 1 = cos(2x)
formula: cos(2x) = 1 - 2sin²x
sin x + 1 = 1 - 2sin²x
2sin²x + sin x = 0
sin x (2sin x + 1) = 0
sin x = 0 or sin x = -1/2
x1 = πk and x2 = -π/6 + 2πk and
x3 = 5π/6 + 2πk
for domain 0≤x<2π :
x1 = 0 (for k=0 in x1)
x2 = π (for k=1 in x1
x3 = 11π/6 (for k=1 in x2)
x4 = 5π/6 (for k=0 in x3).
k is an integral.
Answer:
This is jibberish
Step-by-step explanation:
Just language please and thanks
The conversions factors needed are 1 mile= 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s
<u>Solution:
</u>
Given, A runner is running 10 miles per hour.
We have to find what conversion factors should be used to convert 10 mi/hr to ft/s?
Now, speed of runner = 10 miles per hour.
But we need the units to be in ft / s.
Then, conversion factors are miles to feet and hours to seconds.
Now, miles to feet ⇒ 1 mile = 5280 feet.
Now, hours to seconds ⇒ 1 hour = 3600 seconds

Hence, the conversions needed are 1 mile = 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s