9=3^2
3^(2x)=(3^2)^(3x-4)
3^(2x)=3^(6x-8)
2x=6x-8
0=4x-8
8=4x
2=x
The missing values are 28° and 62°
<h3>What are perpendicular lines?</h3>
Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.
From the information given, we have that;
Line AC ⊥ Line BE
Where:
- m ∠ ADE = (x + 5)°
- m ∠ DBE = (3x - 7)°
Hence,
x + 5 + 3x - 7 = 90
collect like terms
4x = 90 + 2
4x = 92
Make 'x' the subject
x = 92/ 4
x = 23
For the missing values
m ∠ ADE = (x + 5)° = ( 23 + 5) = 28°
m ∠ DBE = (3x - 7)° = (3(23) - 7) = 62°
Thus, the missing values are 28° and 62°
Learn more about perpendicular lines here:
brainly.com/question/17683061
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(6, 2 )
substitute x = 5 into the equation and solve for y
6y + 8 = 20 ( subtract 8 from both sides )
6y = 12 ( divide both sides by 6 )
y = 
= 2
the ordered pair is (5, 2 )
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Step-by-step explanation:
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