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umka21 [38]
3 years ago
13

What is the thousandths value in 62.407

Mathematics
1 answer:
den301095 [7]3 years ago
6 0
The thousandths value is 7.
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Y = x – 6 x = –4 what is the solution to the system of equations? (–8, –4) (–4, –8) (–4, 4) (4, –4
fredd [130]

Answer:

(- 4, - 10 )

Step-by-step explanation:

Given the 2 equations

y = x - 6 → (1)

x = - 4 → (2)

Substitute x = - 4 into (1) for corresponding value of y

y = - 4 - 6 = - 10

Solution is (- 4, - 10 )

4 0
3 years ago
Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Third-degree, with zeros of −3
RSB [31]

Answer:

\Large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}

Step-by-step explanation:

Hello,

Based on the indication, we can write this polynomial as below, k being a real number that we will have to identify (degree = 3 and we have three zeroes -3, -1, and 2).

   \Large \boxed{k(x+3)(x+1)(x-2)}

We know that the point (1,10) is on the graph of this function, so we can say.

k(1+3)(1+1)(1-2)=10}\\\\4*2*(-1)*k=10\\\\-8k=10\\\\k=\dfrac{10}{-8}=-\dfrac{5}{4}

Then the solution is:

\large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 mil
devlian [24]

Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

This is 1 subtracted by the p-value of Z when X = 84.

So, Z = (84-87)/6

Z = -3/6

Z = -0.5 has a p-value of 0.30854.

⇒1 - 0.30854 = 0.69146

  • 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.

Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)

7 0
3 years ago
I need help with the answers
vlada-n [284]

Answer:

i dont get it

Step-by-step explanation:

4 0
3 years ago
Find the area of the triangle with the given base and height.<br> b = 3 m and h = 10 1/2 m
svetoff [14.1K]

<u>Statement</u><u>:</u>

The base of a triangle is 3m and its height is 10 \frac{1}{2} m.

<u>To </u><u>find </u><u>out:</u>

The area of the triangle.

<u>Solution:</u>

  • Given, base = 3m, height = 10 \frac{1}{2}m
  • We know,

\sf \: area \:  \:  of \:  \: a \:  \: triangle =  \frac{1}{2}  \times base \:  \times height

  • Therefore, the area of the triangle

\sf =  (\frac{1}{2}  \times 3 \times 10 \frac{1}{2} ) {m}^{2}  \\ \sf  = ( \frac{1}{2}  \times 3 \times  \frac{21}{2} ) {m}^{2}  \\  = \sf  \frac{63}{4}  {m}^{2}  \\  =   \sf 15\frac{3}{4}  {m}^{2}

<u>Answer</u><u>:</u>

The area of the triangle is \sf \: 15 \frac{3}{4}  {m}^{2}

Hope you could understand.

If you have any query, feel free to ask.

5 0
2 years ago
Read 2 more answers
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