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tigry1 [53]
3 years ago
15

Compare: 10 quarts and 2.5 gallons *

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0
10 quarts = 2.5 gallons
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Hi, I am very stuck on questions 17 and 18. Can someone help please? Thanks
NISA [10]

9514 1404 393

Answer:

  17) x = 10√2

  18) x = 4√6

Step-by-step explanation:

These problems rely on your knowledge of the side ratios of special triangles

  45°-45°-90° triangle: 1 : 1 : √2

  30°-60°-90° triangle: 1 : √3 : 2

__

17) 5 is the short side of the isosceles right triangle, so its hypotenuse is 5√2. That length is the shortest side of the 30/60/90 triangle, so its longest side is 2 times that:

  x = 10√2

__

18) 8 is the longest side of the 30/60/90 triangle, so its long leg will be 8(√3)/2 = 4√3. The hypotenuse of the isosceles right triangle is √2 times that, so ...

  x = (4√3)(√2)

  x = 4√6

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3 years ago
A nutritionist worked off 5,500 calories yesterday. Today, she worked off 2,700 calories. What is the percent decrease in the nu
marysya [2.9K]

Answer: 50.9091 percent

5 0
2 years ago
You have taken up gardening for relaxation and have decided to fence in your new rectangular shaped masterpiece. The length of t
sineoko [7]

Answer:

Step-by-step explanation:

It appears i cant answer your question but what i can do is provide this paragraph as a trade for points. Appreciate your help. :)

3 0
4 years ago
Please answer right away!!!
liraira [26]

Answer:

22.9m

Step-by-step explanation:

Using Pythagorean theorem, we can get two equations using the angles.

From Point A:

∠A = 20°

AB = 20m

From Point B:

∠B = 29°

BD = x

What we are looking for is the opposite side of each right triangle, each person makes because we have one adjacent side. We also know that both opposite sides will be equal.

So we use this formula for both point of views:

Tan\theta=\dfrac{Opposite}{adjacent}

Where:

Opposite = height of the building

Adjacent = distance from the building

We are looking for the opposite side so we can tweak our formula to get an equation for the height

height=(Tan\theta)(distance)

Using our given, we can solve for the distance of point B to D:

(Tan20)(20+x) = (Tan29)(x)\\\\(0.3640)(20+x) = (0.5543)(x)\\\\\dfrac{(7.28+0.3640x)}{0.5543}=x\\\\13.1337 + 0.6567x = x\\\\13.1337 = x - 0.6567x\\\\13.1337 = 0.3433x\\\\\dfrac{13.1337}{0.3433}=x\\\\38.2572 = x

The distance of point B to D is 38.2572 m.

Now that we know the distance of BD we can solve for the height of the building using only the given from point B.

height=(Tan\theta)(distance)

height=(Tan29)(38.2572m)

height=(0.5543)(38.2572m)

height=21.21m

But this is only the height from the line of sight. To get the height of the building from the ground, we just add the height of the viewer, which is 1.7m.

21.21m + 1.7m = 22.91m

The closest answer is: 22.91 m

8 0
4 years ago
The sum of a number, n, and a number 5 larger than it is 41. Which of the following equations could be used
Afina-wow [57]
I think it (3) one I’m not sure
3 0
3 years ago
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