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QveST [7]
3 years ago
13

Pls help as fast as u can

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

Step-by-step explanation:

a)4.67

b) 2.27

do you not have a calculator?   :/

Dima020 [189]3 years ago
4 0

Answer:

a. $2.2

b. $2.2

Step-by-step explanation:

Not completely sure if it's right for part b, but 100% sure my answer for part a is right.

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-4x+6(x-1) simplify algebraic expression
vladimir1956 [14]

Hey there

the answer is

−4x+6(x−1)

Distribute:

=−4x+(6)(x)+(6)(−1)

=−4x+6x+−6

Combine Like Terms:

=−4x+6x+−6

=(−4x+6x)+(−6)

=2x+−6

thank you

       .   OFFICIALLYSAVAGE2003

7 0
3 years ago
Urgently NEED these questions answered!!!!!
Len [333]
What questions? You didn't write any?
6 0
3 years ago
Anyone know this because I need help !!!!
Mila [183]

Answer:

90 clockwise

Step-by-step explanation:

rotate it by 90 degrees. it lines up

5 0
3 years ago
Read 2 more answers
Write the point-slope form of the equation of the line through the given point woth the given slope
Andrej [43]

Answer:

3.) \displaystyle y - 4 = 4[x - 1]

2.) \displaystyle y + 5 = 2[x + 2]

1.) \displaystyle y + 3 = 1\frac{1}{5}[x + 5]

Step-by-step explanation:

In the Point-Slope Formula, \displaystyle y - y_1 = m[x - x_1],all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

* \displaystyle 1\frac{1}{5} = \frac{6}{5}

I am joyous to assist you anytime.

3 0
3 years ago
a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
3 years ago
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