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3 years ago

Which of the following points satisfies the inequality x ≥ -3? (select all that apply) a(0, -2) b(-3, 4) c(-4, 2) d(5, -5)

Mathematics

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

a, b, d

Step-by-step explanation:

For the inequality x ≥ -3 . . .

a(0, -2) . . . 0 ≥ -3, true

b(-3, 4) . . . -3 ≥ -3, true

c(-4, 2) . . . -4 ≥ -3, FALSE

d(5, -5) . . . 5 ≥ -3, true

Points a, b, d satisfy the inequality.

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Which expression is equivalent

Rudik [331]

Answer:

the answer is 1/27. C :))

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you have a piece of wood that is 72 inches long u cut the wood into three pieces the second piece is 6 inches longer than the fi

tangare [24]

Let

x---------> the length of the first piece

y---------> the length of the second piece

z---------> the length of the third piece

we know that

x+y+z=72 -------> equation 1

y=x+6 -----> solve for x

x=y-6 -------> equation 2

z=6+y -------> equation 3

substitute equation 2 and equation 3 in equation 1

[y-6]+y+[6+y]=72

3y=72

y=(72/3)=24 in

Find the value of x

x=y-6 -------> equation 2

x=24-6=18 in

Find the value of z

z=6+y -------> equation 3

z=6+24=30 in

therefore

the answer is

the length of the first piece is 18 in

the length of the second piece 24 in

the length of the third piece is 30 in

7 0

3 years ago

In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s

MaRussiya [10]

Answer:

The mentioned number in the exercise is:

362

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

x = hundredths digit
y = tens digit
z = ones digit

We can write:

x = z + 1 (the hundreds digit is one more than the ones digit).
y = 2x (the tens digit is twice the hundreds digit).
x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

x + y + z = 11
(z + 1) + y + z = 11 (remember x = z + 1)
z + 1 + y + z = 11
z + z +y + 1 = 11 (we just ordered the equation)
2z + y + 1 = 11 (z + z = 2z)
2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
2z + y = 10
2z + (2x) = 10 (remember y = 2x)
2z + 2x = 10
2z + 2(z + 1) = 10 (x = z + 1 again)
2z + 2z + 2 = 10
4z + 2 = 10
4z = 10 - 2
4z = 8
z = 8/4
z = 2

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

x = z + 1
x = 2 + 1
x = 3

And we'll use the second equation to obtain the value of y (the tens digit):

y = 2x
y = 2(3)
y = 6

Organizing the digits, we obtain the number:

Number = xyz
Number = 362

As you can see, the obtained number is 362.

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Answer:

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2 years ago

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strojnjashka [21]

Answer:

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Step-by-step explanation:

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