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Sergio [31]
3 years ago
15

Help me please 10 points

Mathematics
1 answer:
Art [367]3 years ago
8 0

Answer:

24

Step-by-step explanation:

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Explain how you solved 42-16
Mkey [24]

Answer:

26

Step-by-step explanation:

42-16=26 because Pi is a number - approximately 3.142. It is the circumference of any circle divided by its diameter. The number Pi, denoted by the Greek letter π - pronounced 'pie', is one of the most common constants in all of mathematics. It is the circumference of any circle, divided by its diameter.

3 0
3 years ago
A zoo has 151515 Emperor penguins. The Emperor penguins make up 30%, percent of all the penguins at the zoo.
Orlov [11]
30% of 151515 would be 45454.5 Emperor Penguins<span />
6 0
3 years ago
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The sum of three numbers is 96. The third number is 6 less than the first. The second number is 3 times the third. What are the
11Alexandr11 [23.1K]
Let the first number be x.

Third number = x - 6

Second number = 3(x - 6) = 3x - 18

Sum of the numbers = 96

x + 3x - 18 + x - 6 = 96

5x -24 = 96

5x = 120

x = 24

Thus,

The first number is 24. The second number is 54. The third number is 18.
6 0
3 years ago
Help please, try to explain it in steps for me if u can't that's fine, ty!
Iteru [2.4K]

Answer:

B

Step-by-step explanation:

We are given that Expression One is:

2\cdot 10^x

And Expression Two is:

4\cdot 10^{x+y}

We are given that the value of Expression Two is 20,000 times greater than the value of Expression One. And we want to find the value of <em>y.</em> In other words:

4\cdot 10^{x+y}=20000(2\cdot 10^x)

We can divide both sides by four:

10^{x+y}=10000\cdot 10^x

Recall that:

x^a\cdot x^b=x^{a+b}

Therefore:

10^x\cdot 10^y=10000\cdot 10^x

Divide both sides by 10ˣ:

10^y=10000

Solve for <em>y: </em>

<em />\displaystyle y = \log_{10}10000 = 4<em />

Our answer is B.

3 0
2 years ago
Find the value of f(3) given f(x) = − 5x + 2​
Verdich [7]

Answer:

- 13

Step-by-step explanation:

Plug 3 in for x:

-5(3)+2

Simplify :

-15+2

=-13

6 0
3 years ago
Read 2 more answers
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