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wariber [46]
3 years ago
8

Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

Answer:

{ \tt{ {x}^{2} +  {y}^{2}  - 6x - 2y + 4 = 0 }}

Center:

{ \tt{(3, \: 1)}}

Radius:

{ \tt{radius =  \sqrt{ {g}^{2} +  {f}^{2} - c  } }} \\  =  \sqrt{36 + 4 - 4}  \\  = 6 \: units

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Step 1: Define Systems</u>

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<u>Step 2: Solve for </u><em><u>s</u></em>

<em>Substitution</em>

  1. Substitute in <em>r</em>:                                4s = 1/2s + 7
  2. Subtract 1/2s on both sides:          7/2s = 7
  3. Divide 7/2 on both sides:              s = 2

<u>Step 3: Solve for </u><em><u>r</u></em>

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  2. Substitute in <em>s</em>:                       r = 4(2)
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