The zeros of this functions are -4, 2, -4, and -4.
-4 is a multiple zero and has multiplicity 3.
2 is a zero. I would call it a simple zero, since it's only a zero once (AKA has multiplicity of 1).
Is this a "pick one answer" or "pick all correct answers"?
Answer:
1.f(x)=2x-5
i will take the set {-2,-1,0,1,2}
f(-2)=2(-2)-5
=-4-5
=-9
f(-1)=2(-1)-5
=-2-5
=-7
f(0)=2(0)-5
=-5
f(1)=2(1)-5
=-3
f(2)=2(2)-5
=-1
so the coordinates of the function is {-9,-7,-5,-3,-1}
2.f(x)=-3x+6
i will the take the set {-2,-1,0,1,2} too
f(-2)=-3(-2)+6=6+6=12
f(-1)=-3(-1)+6=3+6=9
f(0)=-3(0)+6=6
f(1)=-3(1)+6=-3+6=3
f(2)=-3(2)+6=-6+6=0
{12,9,6,3,0}
3.f(x)=2/3.x+4
{-2,-1,0,1,2}
f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3
f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3
f(0)=2/3(0)+4=4
f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3
f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3
{8/3,10/3,4,14/3,16/3}
you're can graph those coordinates
actually you can take other coordinates...
CMIIW
,
X = 80
y = 85
If you look at only the left triangle, you can see that x is part of one of the angles. The 3 interior angles of the triangle add up to 180 degrees, so subtracting the other two angles, you get x + 30 = 110, or x = 80.
The same method can be used for the other triangle to find y.
-6x-x^2-8 = -(x+2) x (x+4)
(This is if you are factoring the expression)
