First, pull out the GCM from the two terms: 3x^6(x^3-64)
Then factor the remains using the difference of cubes: 3x^6(x-4)(x^2+4x+16)
Answer:
9x^2 - 3x - 2, R -7.
Step-by-step explanation:
x - 5) 9x^3 - 48x^2 + 13x + 3(9x^2 - 3x - 2 <---- Quotient.
9x^3 - 45x^2
- 3x^2 + 13x
-3x^2 + 15x
-2x + 3
-2x + 10
-7 <----- Remainder
Answer:
7.66
Step-by-step explanation:
Just open the parenthesis.
4x-4+4x+4x-4=84
Now simplify and solve
12x-8=84
12x=92
x= 7.66
Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
we have

The solution is the shaded area above the dotted line
therefore
The answer in the attached figure