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ahrayia [7]
3 years ago
8

How to solve (3x+2) (4x-9)

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Answer:

=12x2−19x−18

Step-by-step explanation:

hope this helps :)

Alika [10]3 years ago
3 0

If you are looking for the values of X, they are 2/3, 9/4

3x+2=0

3x=2

X=2/3

4x-9=0

4x=9

X=9/4

If you are looking for the multiplication, it is on this picture:

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5.5 = -2 + d
TEA [102]
The value of <em>d</em> is 7.5.

The key to solving equations is doing the inverse, or opposite, function/process.
For example, you subtract when d + 1 = 2:
d + 1 = 2
(d + 1) -1 = (2) - 1
d = 1

In the same way, you add values when you have a negative:
5.5 = -2 + d = d - 2
5.5 = d - 2
(5.5) + 2 = (d - 2) + 2
7.5 = d

Now if instead of adding 2, you subtract 2, the problem becomes:
5.5 = d - 2
(5.5) - 2 = (d - 2) - 2
3.5 = d - 4

This doesn't solve your problem, it just makes the value needed to be canceled out larger.

Thus d = 7.5 and you will add because the value is negative.
7 0
3 years ago
Read 2 more answers
Please help me ASAP!!!
natka813 [3]

Question:

Solution:

Let the function

y=f(x)\text{ = }\sqrt[]{x}-9

Now remember the following rule:

To graph y = f(cx)

if 0 < c < 1 , stretch the graph of y = f(x) horizontally by a factor of 1/c.

Thus, applying this to the given function, with c = 3, we can conclude that the correct answer is:

y=f(x)\text{ = }\sqrt[]{\frac{1}{3}x}-9

5 0
8 months ago
What is the absolute value of -36
goblinko [34]

Answer:

36

Step-by-step explanation:

absolute value of -36 is 36

3 0
3 years ago
If f(x)= - 4x-4, g(x)= 4x² + 4x + 2, and h(x)= 3x2 – 3, find f(3).
Deffense [45]

Answer:

f(3) = -16

Step-by-step explanation:

Given

f(x)= - 4x-4

g(x)= 4x^2 + 4x + 2

h(x)= 3x^2 - 3

Required

f(3)

We have:

f(x)= - 4x-4

Substitute x = 3

f(3) = -4 * 3 - 4

f(3) = -12 - 4

f(3) = -16

Hence:

f(3) = -16

6 0
2 years ago
Which expression has the same value as m-4 + 1/5-4
frutty [35]
If its m-4 + 1/5-4, it's b
if you meant m^-4 + (1/5)^-4, it should be a
7 0
2 years ago
Read 2 more answers
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