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8_murik_8 [283]
3 years ago
12

A ball is launched horizontally at 150 m/s from a cliff. What is its vertical speed after 3 seconds?

Physics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

v_f = 30 m/s

Explanation:

v_f = v_I + a*t

v_f = 0m/s + (9.81m/s²)*(3s)

v_f = 29.43m/s

v_f = 30 m/s

Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.

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The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

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x is the length by which spring got stretched =?

The stretch of the spring is found as;

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Hence the length by which the spring got stretched will be 0.08 m.

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