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GalinKa [24]
3 years ago
14

Plz answer brainliest if right!

Physics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer: it is D. it is the only possible answer. use the process of elimination. which answers make sense?

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the power rating of an electric lawn mower is 2200 watts. if the lawn mower was used for 30 mins, and 650 Newtons of force was u
Tasya [4]

Answer:

Calculate the work done by a 47 N force pushing a 0.025 kg pencil 0.25 m ... A boy on a bicycle drags a wagon full of newspapers at 0.80 m/s for 30 min ... A power mower does 9.00 x 105 J of work in 0.500 h. ... p: W 2200ch: w will320,000 T/ ... How much electrical energy (in kilowatt hours) would a 60.0 W light bulb use in ..

Explanation:

4 0
3 years ago
It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the el
Aneli [31]

Answer:

P=4801.5

Explanation:

Given :

work done = W = 100,832 J

time = 21.0 sec

Find:

P = ?

Formula:

P = W/t

Solution:

P = W/t

P = 100,832/21.0

  =  4801.52 J/s or Watts

6 0
4 years ago
HELP!!!
nekit [7.7K]
The answer is D. The Moon's gravitational pull
6 0
3 years ago
Read 2 more answers
Identify forces between two objects which are inversely proportional to the square of the distance between them. i. nuclear forc
nikdorinn [45]
The force between two celestial bodies is a Newtonian gravitational force. 
It is also called Newton's law of universal gravitation. We can write it down mathematically in the following way:
F=G \frac{ m_{1} m_{2} }{ r^{2}}
We can see from this formula that gravitational force is <span>inversely proportional to the square of the distance between bodies.
The electrostatic force between two charges is Coulombs force. We can write it down like this: 
</span>F= k_{e} \frac{ q_{1} q_{2} }{ r^{2}}
This force is also inversely proportional to the square of the distance between interacting particles.
The nuclear force is a little bit more complicated. It can be expressed using the so-called Yukawa potential, which has the following form:
V_{y} =- g^{2} \frac{ e^{-ur} }{r}
This interaction does not follow the inverse-square law.
The final answer should be 8.
3 0
3 years ago
A speeding car traveling at 24.8 m/s passes a police car that is at rest. The police car begins its pursuit at the instant the s
marusya05 [52]

Answer:

the acceleration required is 1.37m/s^2

Explanation:

The car is having a constant velocity movement, so if we calculate the time to reach 897m, we can use it to find the acceleration the policeman need to apply to reach the car.

x=v*t\\t=\frac{x}{v}\\t=\frac{897m}{24.8m/s}\\t=36.17s

the policeman is traveling with a constant acceleration starting from rest so:

x=\frac{1}{2}*a*t^2\\\\a=\frac{2*x}{t^2}\\\\a=1.37 m/s2

7 0
3 years ago
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