All categories

3 years ago

Can someone help me with this problem 7.984 ÷ 1.99

Mathematics

1 answer:

kiruha [24]3 years ago

3 0

Answer: 4.012

Step-by-step explanation: Hope this helps! :)

You might be interested in

I may need some help

VikaD [51]

i have to poop hhhhhjhhjhjhjhjhjhjhh

8 0

3 years ago

Read 2 more answers

As part of a physics experiment, Ming drops a baseball from the top of a 315-foot building. To the nearest tenth of a second, fo

artcher [175]

Answer: 4.4 seconds

Step-by-step explanation:

h(t) = -16t² + 315

Since we want to find the total time the baseball is in the air, we need to find the time (t) when the ball lands on the ground --> h(t) = 0

0 = -16t² + 315

-315 = -16t²

$\dfrac{315}{16}=t^2\\\\\\\sqrt{\dfrac{315}{16}}=t\\\\\\\dfrac{\sqrt{315}}{4}=t\\\\\\\large\boxed{4.4=t}$

6 0

3 years ago

Read 2 more answers

Sheryl has 4 more than one-third as many pairs of shorts as Katie has. If Katie has x pairs of shorts, which expression describe

svetoff [14.1K]

I think the answer is c 1/3x+4

5 0

3 years ago

Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t

noname [10]

Answer:

a. $y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}$

b $y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x$

Step-by-step explanation:

1. $y''-4y'+4y=6x e^{2x}$

Auxillary equation

$D^2-4D+ 4=0$

$(D-2)(D-2)=0$

D=2,2

Then complementary solution = $C_1e^{2x}+C_2xe^{2x}$

Particular solution $=\frac{6 xe^{2x}}{(D-2)^2}$

D is replace by D+2 then we get

P.I= $\frac{6xe^{2x}}{0}$

P.I= $\frac{e^{ax}}{D+a} \cdot .V$

where V is a function of x

P.I= $\frac}x^3e^{2x}$

By integrating two times

Hence, the general solution

$y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}$

b.y''+9y=5 cos x-7 sin x

Auxillary equation

$D^2+9=0$

D= $\pm 3i$

$C.F=c_1 cos 3x+ c_2sin 3x$

P.I= $\frac{5 cos x-7 sin x}{D^2+9}$

P.I= $\frac{sin ax}{D^2+bD +C}$

Then D square is replace by -a square

$D^2$ is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

$y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x$

4 0

3 years ago

Find the value of x. A. 6+3√5 m B. 5√3 m C. 2√ 41m D. 6 m

kirill115 [55]

Answer:

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to solve for x

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 8² + 10² = 64 + 100 = 164 ( take the square root of both sides )

x = $\sqrt{164}$

= $\sqrt{4(41)}$

= $\sqrt{4}$ × $\sqrt{41}$ = 2 $\sqrt{41}$ → C

7 0

4 years ago