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Pani-rosa [81]
3 years ago
7

Type the correct answer in each box, starting with the intercept with the lower value.

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

x-intercept(s):  ( 8 , 0 ) , ( − 3 , 0 )

y-intercept(s):  ( 0 , 24 )

Natalka [10]3 years ago
5 0
-(- x - 8) (x + 3)
hope this helps<3
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A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo
Roman55 [17]

The tower is 61.65 meters tall.

<u>SOLUTION: </u>

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.  

At the same time, a nearby tower casts a shadow that is 36.25 m long.  

We have to find height of the tower.  

Now, we know that,

2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }

Then, (let it be) n meter tall \rightarrow 36.25 long shadow

So, by cross multiplication method,

\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}

This can be written as,

\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}

Cross multiplications steps: (To find Single Variable)

  1. Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
  2. Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
  3. Set the two products equal to each other.
  4. Solve for the variable.
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3 years ago
Add then divide.<br> Evaluate<br> (7.3 X 10) + (2.4 X 107)<br> (4 X 104)
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19-15 gives us a total of 4 students over the course of the year!

So the value of C is 4 students
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