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Artyom0805 [142]
3 years ago
15

A city block has 3 stores and a 20 foot mural on one side of the street. On the other side of the street there are 5 stores. If

all the storefronts are equal length, what's the length of the city block?
Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

  50 ft

Step-by-step explanation:

Apparently, the 20 ft mural has the same width as 2 storefronts. So each storefront is 10 ft, and 5 of them have a length of 50 feet.

The length of the city block is 50 feet.

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Correct one gets Brainly :D (pls help)
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Answer:

i wanna say 30 cm?

Step-by-step explanation:

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2(x+1)+3x=37 *what is x??​
irina1246 [14]

2(x+1)+3x=37

simplifythe left side:

2x +2 +3x = 37

Combine like terms:

5x +2 = 37

Subtract 2 from both sides:

5x = 35

Divide both sides by 5:

x = 7

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The products of respiration are the_____
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Step-by-step explanation:

Powerhouse of photo synthesis

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2 years ago
Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]
Anit [1.1K]

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\

put the value of d in equation (iv):

\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

4 0
3 years ago
100 stickers are evenly divided between 16 children how many stickers will be left over at the end
puteri [66]

Answer:

4

Step-by-step explanation:

First, we can know our multiplication charts and know that 16 x 6 = 96

96 is the closest we can get to 100 while still having a remainder, which is 4

4 is the remainder, and is the amount left over.

8 0
3 years ago
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