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Softa [21]
2 years ago
6

I need help on this 6th grade math question: its for 20 points

Mathematics
2 answers:
Vadim26 [7]2 years ago
7 0
Quadrant I i got it correct
otez555 [7]2 years ago
3 0

Answer:

  • Quadrant I.

Step-by-step explanation:

<u>Quadrant I examples:</u>

  • (2, 5)
  • (3, 4)
  • (7, 1)

<u>Quadrant II examples:</u>

  • (-1, 5)
  • (-6, 2)
  • (-4, 7)

<u>Quadrant III examples:</u>

  • (-3, -4)
  • (-7, -1)
  • (-8, -5)

<u>Quadrant IV examples:</u>

  • (5, -6)
  • (1, -4)
  • (8, -2)
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X + 2y =6<br> X- y =3<br> Solution?
VikaD [51]
Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.

x+2y=6
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Multiply the bottom equation by two so then you have:

x+2y=6
2x-2y=6

The y's now cancel out:

x=6
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Add them together

3x=12

Divide

x=4.

To find y, plug x into either equation (*don't have to do both, but I will)

(4)+2y=6
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Subtract four

2y=2
-y=-1

Divide each

2y/2 = 2/2
y=1

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The answer is:
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I hope that helps!
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