All categories

2 years ago

Help asap please 50 points

Mathematics

2 answers:

Marysya12 [62]2 years ago

6 0

Answer:

Step-by-step explanation:

Bro this is hard and i think this is on a test so... i dont know lol thanks for the 25 points

Allushta [10]2 years ago

6 0

Answer:

The area of rectangle is 8 x ² y ².

Step-by-step explanation:

<h3>Given that :- </h3>

Measure of side A of rectangle is 2 xy
Side B measure twice the length of side A = 2 × ( 2xy ) = 4 xy

➛ Area of rectangle

<h3>Formula Used :-</h3>

➛ Area of rectangle = Length × Breadth

<h3>Solution :-</h3>

Firstly we need to find Breadth of rectangle

Using Formula

Area of rectangle = Length × Breadth

Where

Length of rectangle = 2xy

Breadth of rectangle = 2 × 2xy = 4 xy

Substituting the values into the Formula

Area of rectangle = 2 xy × 4 xy

multiply, we get

Area of rectangle = 8 x² y²

Therefore, Area of rectangle is 8 x ² y ².

You might be interested in

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0

2 years ago

JUST DO 6 and 22 pleasss!!!

Hatshy [7]

Answer:

Step-by-step explanation:

x=intercept is when the line intersect with the x axis when y=0

6: x intercept (1,0)

y intercept is when the line intersect with y axis at certain point or when x=0

y intercept (0.-24)

22: (8,0) x intercept

(0 , 4) the y-intercept

8 0

3 years ago

What is the x-intercept of the line with this equation 13x+y=−15 ? Enter your answer in the box. ( , 0)

Nastasia [14]

Answer: The required x-intercept of the given line is $\left(-\dfrac{15}{13},0\right).$

Step-by-step explanation: We are given to find the x-intercept of the line with the following equation :

$13x+y=-15~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

x-intercept of a line is a point on the line where the line crosses the x-axis, that is y co-ordinate is 0.

Substituting y = 0 in equation (i), we get

$13x+y=--15\\\\\Rightarrow 13x+0=-15\\\\\Rightarrow 13x=-15\\\\\Rightarrow x=-\dfrac{15}{13}.$

Thus, the required x-intercept of the given line is $\left(-\dfrac{15}{13},0\right).$

4 0

3 years ago

Use multiplication and distributive property to find the quotient of 75 divided by 3

mezya [45]

The answer would be 23

4 0

3 years ago

Read 2 more answers

Find the derivative: y={ (3x+1)cos(2x) } / e^2x

DochEvi [55]

Answer:

$\displaystyle y' = \frac{3cos(2x) -2(3x + 1)[sin(2x) + cos(2x)]}{e^{2x}}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Factoring
Exponential Rule [Dividing]: $\displaystyle \frac{b^m}{b^n} = b^{m - n}$
Exponential Rule [Powering]: $\displaystyle (b^m)^n = b^{m \cdot n}$

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Quotient Rule: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Trig Derivative: $\displaystyle \frac{d}{dx}[cos(u)] = -u'sin(u)$

eˣ Derivative: $\displaystyle \frac{d}{dx}[e^u] = u'e^u$

Step-by-step explanation:

<u>Step 1: Define</u>

$\displaystyle y = \frac{(3x + 1)cos(2x)}{e^{2x}}$

<u>Step 2: Differentiate</u>

[Derivative] Quotient Rule: $\displaystyle y' = \frac{\frac{d}{dx}[(3x + 1)cos(2x)]e^{2x} - \frac{d}{dx}[e^{2x}](3x + 1)cos(2x)}{(e^{2x})^2}$
[Derivative] [Fraction - Numerator] eˣ derivative: $\displaystyle y' = \frac{\frac{d}{dx}[(3x + 1)cos(2x)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{(e^{2x})^2}$
[Derivative] [Fraction - Denominator] Exponential Rule - Powering: $\displaystyle y' = \frac{\frac{d}{dx}[(3x + 1)cos(2x)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{e^{4x}}$
[Derivative] [Fraction - Numerator] Product Rule: $\displaystyle y' = \frac{[\frac{d}{dx}[3x + 1]cos(2x) + \frac{d}{dx}[cos(2x)](3x + 1)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{e^{4x}}$
[Derivative] [Fraction - Numerator] [Brackets] Basic Power Rule: $\displaystyle y' = \frac{[(1 \cdot 3x^{1 - 1})cos(2x) + \frac{d}{dx}[cos(2x)](3x + 1)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{e^{4x}}$
[Derivative] [Fraction - Numerator] [Brackets] (Parenthesis) Simplify: $\displaystyle y' = \frac{[3cos(2x) + \frac{d}{dx}[cos(2x)](3x + 1)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{e^{4x}}$
[Derivative] [Fraction - Numerator] [Brackets] Trig derivative: $\displaystyle y' = \frac{[3cos(2x) -2sin(2x)(3x + 1)]e^{2x} - 2e^{2x}(3x + 1)cos(2x)}{e^{4x}}$
[Derivative] [Fraction - Numerator] Factor: $\displaystyle y' = \frac{e^{2x}[(3cos(2x) -2sin(2x)(3x + 1)) - 2(3x + 1)cos(2x)]}{e^{4x}}$
[Derivative] [Fraction] Simplify [Exponential Rule - Dividing]: $\displaystyle y' = \frac{3cos(2x) -2sin(2x)(3x + 1) - 2(3x + 1)cos(2x)}{e^{2x}}$
[Derivative] [Fraction - Numerator] Factor: $\displaystyle y' = \frac{3cos(2x) -2(3x + 1)[sin(2x) + cos(2x)]}{e^{2x}}$

Topic: AP Calculus AB/BC

Unit: Derivatives

Book: College Calculus 10e

6 0

3 years ago