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2 years ago

-2 2/3 divided by 1 5/6 + 2 NO MIXED NUMBERS

Mathematics

2 answers:

Kay [80]2 years ago

7 0

Answer:

6/11

Step-by-step explanation:

-2 2/3 divided by 1 5/6 = -16/11 and when you add two to that you get 6/11.

oksano4ka [1.4K]2 years ago

4 0

Answer:

14/15

Step-by-step explanation:

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worty [1.4K]

Answer: if 28 is 6 meters, 14 is 3 meters. 14 times 3 is 42

Step-by-step explanation: WAIT I WAS THINKING WRONG DONT LISTEN TO ME!

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3 years ago

A line has a slope of Negative one-half and a y-intercept of –2. What is the x-intercept of the line?

Mkey [24]

Answer:

it's -4

Step-by-step explanation:

I just took the test and got it right

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3 years ago

Given the triangle below, which of the following is a correct statement? Right triangle ABC with AB measuring 5, AC measuring 6,

Elanso [62]

Drawing a diagram to match this figure, BC would have to be the hypotenuse as it is the longest side of the triangle. Angle A would have to be the right angle.
For the first choice, $\cot B = \frac{1}{ \tan B} 
\\ = \frac {1}{\frac {6}{5}}
\\ = 1 \div \frac{6}{5} = \frac{1}{1} \div \frac{6}{5}
\\ = \frac{1}{1} * \frac{5}{6} = \frac{5}{6}$ . The first choice is not correct.
The second choice gives us $\csc C= \frac{1}{ \sin C}= \frac{1}{\frac {5}{8}}
\\ = 1 \div \frac{5}{8} = \frac{1}{1} \div \frac{5}{8}
\\ = \frac{1}{1} * \frac{8}{5} = \frac{8}{5}$ . The second choice is not correct either.
The third choice gives us

6 0

3 years ago

To find the height of a pole, a surveyor moves 120 feet away from the base of the pole and then, with a transit 8 feet tall, mea

Vikki [24]

Refer to the figure.
Let AB be the height of the pole; CD be the height of the transit; BC is the distance from the base of the pole to the transit.

Triangle ADE is a right triangle with angle D measuring 26 degrees. Using the tangent function, we have
$tan\:26^{\circ} =\frac{AE}{120}$
So,
$AE=120\:tan\:26^{\circ}$
$AE=58.53\:$

Therefore, the overall height of the pole is
$AB=58.53+8=66.53\:feet$

The height of the pole is 66.53 feet.

6 0

3 years ago

Rectangle MNOP is shown below. Aiden argues that MNQ is congruent to POQ. What triangle congruence criteria proves that MNQ is c

Katena32 [7]

Answer:

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Step-by-step explanation:

Given:

m∠NQM = 40°

m∠NQO = 100°

MNOP is a Rectangle

So we can say that:

Property of rectangle:

All angles of rectangle are 90°

Opposite sides of Rectangle are equal and parallel to each other

MN ≅ PO (opposite side of rectangle)

∠NMQ ≅ ∠OPQ (Both angles are 90°)

Now By Straight Angle property

m∠NQM + m∠NQO + m∠OQP = 180° (angles of straight line)

Substituting the values we get;

40° + 100° + m∠OQP = 180°

140° + m∠OQP = 180°

m∠OQP = 180° - 140° = 40°

So m∠OQP = m∠NQM = 40°

m∠OQP ≅ m∠NQM (Equals angles are congruent to each other)

Hence In Δ MNQ and Δ POQ

m∠OQP ≅ m∠NQM

∠NMQ ≅ ∠OPQ (Both angles are 90°)

MN ≅ PO (opposite side of rectangle)

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Hence Proved...

7 0

3 years ago