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inn [45]
3 years ago
9

Help me right now pls ?!

Mathematics
2 answers:
abruzzese [7]3 years ago
5 0

Answer:

B) =−7j−k−1

Step-by-step explanation:

10k+17-7j-18-11k what we have

=(−7j)+(10k+−11k)+(17+−18) combine like terms

=−7j−k−1

vichka [17]3 years ago
4 0

Answer:

-7j-k-1

Step-by-step explanation:

for this problem you have to subtract the like terms while following the order of the equation (start with the terms on the left and move terms)

Step 1:

-7j has no like terms

= -7j

Step 2:

10k and -11k are like terms

10k-11k

= -1k

Step 3:

17 and -18 are like terms

17-18

= -1

Step 4:

put all simplified terms together

=-7j-k-1

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✦ 5.7735= \frac{x}{4.4}
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4 0
3 years ago
A radioactive compound with mass 470 grams decays at a rate of 3% per hour. Which
xxTIMURxx [149]

After 6 hours the radioactive compound with mass 470 grams becomes 391.49 grams and the equation will be C is equal to 470(1-0.03)^6.

<h3>What is exponential decay?</h3>

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

We know the decay can be as:

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Thus, after 6 hours the radioactive compound with mass 470 grams becomes 391.49 grams and the equation will be C is equal to 470(1-0.03)^6.

Learn more about the exponential decay here:

brainly.com/question/14355665

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3 0
2 years ago
What are the numbers in the smallest group of repeating digits when 41/11 is converted to a nonterminating decimal?
harkovskaia [24]

Answer:

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Step-by-step explanation:

also im not really too sure on my answer so check other answers for a more reliable answer

7 0
3 years ago
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4 years ago
Read 2 more answers
Can someone please help me with this
Alex_Xolod [135]

Answer:

  135°

Step-by-step explanation:

The reference angle appears to be about 45°, so a reasonable estimate of the angle size is 180° -45° = 135°.

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You can do an eyeball comparison with the figure attached to see that the angle is about 135°

This is also the value I see when I place my protractor against the screen.

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