Answer:
The nonzero vector orthogonal to the plane is <-9,-8,2>.
Step-by-step explanation:
Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).


The nonzero vector orthogonal to the plane through the points P,Q, and R is


Expand along row 1.




Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.
4 sq.units
area of a rectangle = length × breadth
length = 4units
breadth = 1units
A = l × b
= 4 × 1
= 4 sq.units
<h3>
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<em>IF</em><em> </em><em>YES</em><em> </em>
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Y=x. I hope that this helped! Good luck! :)
Answer:
find the area and then multiply
Step-by-step explanation:
Answer:
100cm = 1m
Thus, one more step should be added to your working to arrive at the final answer:
Perimeter
= 10m 160cm
= 11m 60cm
This is because 160cm= 100cm +60cm, which is also equivalent to 1m 60cm.
Alternative working:
Convert all the units to cm first.

Length
= 5m 55cm
= 300cm +55cm
= 355cm
Breadth
= 2m 25cm
= 200cm +25cm
= 225cm
Perimeter
= 2(length +breadth)
= 2(355 cm +225 cm)
= 2(580 cm)
= 1160 cm
= 11m 60cm
From the second last step to the last step, you could divide 1160 by 100 to find how many meters are there. You would get a quotient of 11 and a remainder of 60. Since this 60 cannot be changed into meters as a whole number, we can leave it as 11m 60cm. Otherwise, it is also correct to leave it as 1160cm or 11.6m unless otherwise stated.
However, 10m 160cm is not preferred since the conversion of cm to m is done partially, as the 160 cm can still be further simplified.