We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
when you simplify 2/4 it equals 1/2. Making them both equal the same.
2/3 when you double the numbers to make a bigger fraction you make 4/6.
2x2 = 4/ 3x3= /6 = 4/6
3/9 simplified is 1/3. Three goes into three one time, making the top one and three goes into 9 three times making the bottom 3.
When 9/12 is rounded down it is equivalent to 3/4
0.35 is the answer of the questions
Answer: 4236
Step-by-step explanation: I used a calculator. If it's wrong, tell your teacher/instructor.
So you add 7 every time so,
28+7=34
34+7=41
if he continues his pattern he will have done 41 sit-ups on Friday
