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trapecia [35]
2 years ago
13

6. Mary worked 27 hours last week. If she gets paid $12/hour, what is her gross pay?

Mathematics
1 answer:
kupik [55]2 years ago
8 0

Answer:

324

Step-by-step explanation:

you would multiply 27 × 12 and that would equal 324

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Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
3 years ago
(NO LINKS) HELP ASAP! THIS IS DUE TODAY! ILL GIVE BRAINLIEST TO DECENT ANSWER AND 20+ POINTS!
IrinaVladis [17]

Answer:

Part A: a histogram

Step-by-step explanation:

Part A:

A histogram would be the best to use since they gave values that are x - y, or a ranged amount for the score.

Part B:

You would set up each value for the scores on the bottom. You would make the number of students on the left in increments of 1 (1,2,3,4,5 etc. )

You would make the first value ( 0-4 ) go up to 4 students.  The second value ( 5-9) would go to 5. The third value ( 10-14 ) would go to 2. The fourth and fifth values ( 15-19 and 20-24 ) would go to 3.

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2 years ago
HELP PLEASE RN ASAP!!!!!
Sergeeva-Olga [200]

Answer:

1/9^15

Step-by-step explanation:

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Parallel lines and midpoint of a segment

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