First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
Answer:
Evaluating Polynomials:
a. f(1) = -10
b. f(-3) = -239
c. f(2)² = 3125
Factoring Polynomials:
a. (x + 1)(x² - 5x + 6) = (x + 1)(x - 3)(x - 2)
b. (x² - x - 6)(x² + 6x + 9) = (x - 3)(x + 2)(x + 3)(x + 3)
c. x³ + 3x² - 4x - 12 = (x + 3)(x - 2)(x + 2)(x - 2)(x + 2)
Answer:
M = 107 degrees
Step-by-step explanation:
JKM = PQR
J = P
J = 33
K = Q
K = 40
R = M
R = 107
Answer:
Neither
Step-by-step explanation:
equation 1 is a negative slope, equation 2 is a positive slope, but with a different slope.
, we have
