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3 years ago

Please help 25 points

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer:

A. 2m^3 +5

Step-by-step explanation:

STALIN [3.7K]3 years ago

6 0

Answer:

Letter A is the answer

Step-by-step explanation:

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What is the value of the expression 4x−y/2y x when x = 3 and y = 3? −3 1 9 18

ziro4ka [17]

(4x - y)/(2y + x) when x = 3 and y = 3 is
(4(3) - 3)/(2(3) + 3) = (12 - 3)/(6 + 3) = 9/9 = 1

5 0

4 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

When adding the numbers 4+9+7+6+3 you can make one group of 10.True or False

Keith_Richards [23]

Answer:

false

Step-by-step explanation:

6 0

3 years ago

Http://prntscr.com/lkz30r What is the value of x? 28 20 36 17

ivolga24 [154]

This is a question that can be solved with Pythagorean Theorem since it is a right triangle. The longest side, 29, is the hypotenuse and the sides 21 and x are the legs. So, the Pythagorean Theorem states,

$c^{2}= a^{2}+ b^{2}$

Where,

c is the Hypotenuse, a and b are the legs. Putting the respective values gives us,

$(29)^{2}= (21)^{2} +x^{2} \\841=441+x^{2} \\400=x^{2} \\20=x$

So, 20 is the side length of x.

ANSWER: 20

5 0

3 years ago

Read 2 more answers

PLEASE HELPP!! Question is in the picture above !!

CaHeK987 [17]

Answer:

<h2>brainleist plz</h2>

Step-by-step explanation:

first lets do the x^2 part

1/2^2 = 1/4

now 1/4 ^3

equals = 1/64

7 0

3 years ago