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Anni [7]
3 years ago
6

What are extraneous solutions to rational and radical equations? How do they arise? How do we check if a solution is extraneous?

Use these equations as examples to help you explain:

Mathematics
1 answer:
Yanka [14]3 years ago
7 0
There are only three and u can do
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Find the quotient and express it in the simplest form
pychu [463]
2i(4+5i)(4-5i) =82i
4+i nothing more can be done it is at simplest form 

so \frac{82i}{4+i} = \frac{82}{17} + \frac{328}{17} i

so your answer is  \frac{82}{17} + \frac{328}{17} i


5 0
3 years ago
Point T(-9,5) lies on the perpendicular bisector of UV. If the
Flura [38]

The coordinate of point V is at (-16, 9)

If Point T(-9,5) lies on the perpendicular bisector of UV, this means that the point divides the line UV into two equal parts

Given the following coordinates

Midpoint T = (-9, 5)

U = (-2, 1)

Required

coordinate of point V

Using the midpoint formulas;

T(x, y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\T(-9, 5) = (\frac{-2+x_2}{2}, \frac{1+y_2}{2})

Get the value if x₂ and y₂

-9 = \frac{-2+x_2}{2}\\-18 = -2+x_2\\x_2 = -18+2\\x_2 = -16\\

Similarly;

5 = \frac{1+y_2}{2}\\10 = 1+y_2\\y_2 = 10-1\\y_2 = 9\\

Hence the coordinate of point V is at (-16, 9)

Learn more here: brainly.com/question/18049211

5 0
2 years ago
Help pleasee, its past due , im sufferingggg
jeyben [28]

Answer:

-11

Step-by-step explanation:

First we plug -2 in for c

4(-2)-3=-8-3=-11

5 0
2 years ago
Kids go cart with a mass of 40 kg has a momentum of 800 kg x m/s. What speed is the go cart traveling?
satela [25.4K]
20 I think. If I’m wrong don’t roast me please.
7 0
3 years ago
It is given that p varies inversely as q. If p = 12 and q = 45 find p, if q is 135.
alexgriva [62]

Answer:

p =4

Step-by-step explanation:

Given

Variation: Inversely

p = 12 when q = 45

Required

Determine p when q = 135

First, we need to determine the relationship between p and q

Since, it is an inverse variation.

The relationship is:

p\ \alpha\ \frac{1}{q}

Convert to an equation

p= k *\frac{1}{q}

p= \frac{k}{q}

Where k = constant of variation

Make k the subject

k = p * q

When p = 12 and q = 45

k = 12 * 45

k = 540

To solve for p when q = 135

Substitute 135 for q and 540 for k in p= \frac{k}{q}

p = \frac{540}{135}

p =4

6 0
2 years ago
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