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prisoha [69]
3 years ago
7

If using the method of completing the square to solve the quadratic equation

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

6x4tj equalls 1n2

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En un informe se dice que la temperatura minima pronosticada es de -24°C y la maxima de -20°C . Si la temperatura minima represe
stiks02 [169]

Answer:

Check Explanation

Step-by-step explanation:

English Translation

In a report it is said that the predicted minimum temperature is -24 ° C and the maximum is -20 ° C. If the minimum temperature represents colder than the maximum temperature, should it not appear on the reverse? Explain your answer.

Solution

No, it shouldn't appear on the reverse. This is because, just as negative numbers work, they decrease, the further we move away from 0.

Celsius temperature scales are calibrated with respect to the freezing point of water. The freezing point of water serves as the reference point and is called the 0°C.

Temperatures higher than the freezing point of water taken on positive values and temperatures lower, take on negative values. The lower the temperature, the bigger the absolute value of the negative value is.

For example, just like In the question provided, -24°C represents a temperature that is 24° lower than the freezing point of water while -20°C represents a temperature that is 20° lower than the freezing point of water. It is evident that -24°C really is a lower temperature than -20°C.

Hope this Helps!!!

3 0
3 years ago
Mike wants to find the confidence interval for a set of data. He knows the sample size and the sample proportion. Which other pi
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Answer:

A

Step-by-step explanation:

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2 years ago
Help integrate: cot^3(x)
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\displaystyle\int\cot^3x\,\mathrm dx=\int\cot^2x\cot x\,\mathrm dx=\int(\csc^2x-1)\cot x\,\mathrm dx
\displaystyle=\int\csc^2x\cot x\,\mathrm dx-\int\cot x\,\mathrm dx

For the first integral, substitute y=\cot x so that \mathrm dy=-\csc^2x\,\mathrm dx. This leaves you with two standard integrals,

=\displaystyle-\int y\,\mathrm dy-\int\cot x\,\mathrm dx
=-\dfrac12y^2+\ln|\cot x+\csc x|+C
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What is the diameter of 2.34561
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You need to round the number to the nearest whole number
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