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Evgesh-ka [11]
3 years ago
11

Label each part. *GIVING BRAINLIEST*

Computers and Technology
1 answer:
ollegr [7]3 years ago
7 0

Answer:

A.) Stator Magnets

B.) Windings

C.) Brushes

D.) Terminals

E.) Commutator

F.) Armature

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Nina is explaining the SQA process to her friend Amanda.
Nezavi [6.7K]
<span>B. Plan
</span><span>C. Planning
yes or no</span>
4 0
3 years ago
Before entering a loop, the first input, or ____, is retrieved.
Virty [35]

Loop is a control structure that causes a statement or group of statements to repeat.Before entering a loop, the first input, or the accumulator where the total will be kept is retrieved to an initial value, usually zero.

3 0
3 years ago
Write a program that calculates the average rainfall for three months. The program should ask the user to enter the name of each
Eduardwww [97]

Answer:

import java.util.Scanner;

public class ANot {

   public static void main(String[] args) {

   Scanner input = new Scanner(System.in);

       System.out.println("Enter the month name:");

       String month1 = input.next();

       System.out.println("Enter the amount of rain for "+month1);

       double month1Rain = input.nextDouble();

       System.out.println("Enter the second month: ");

       String month2 = input.next();

       System.out.println("Enter the amount of rain for "+month2);

       double month2Rain = input.nextDouble();

       System.out.println("Enter the Third month: ");

       String month3 = input.next();

       System.out.println("Enter the amount of rain for "+month3);

       double month3Rain = input.nextDouble();

       double averageRainfall = (month1Rain+month2Rain+month3Rain)/3;

       System.out.printf("Average Rainfall is: %,.2f  ", averageRainfall);

   }

}

Explanation:

This is written in Java Programming language

  1. Import  the scanner class to prompt user for the inputs (Months and amount of rainfall for each month)
  2. Find the average of the three rainfall amount by adding up and dividing by 3
  3. Output the average. Pay particular attention to the use of java's printf in order to print the average to 2 decimal places
8 0
3 years ago
What does the following code print?double[] myList = {1, 5, 5, 5, 5, 1};double max = myList[0];int indexOfMax = 0;for (int i = 1
Liula [17]

Answer:

This code will print: 4

Explanation:

Following is the step-by-step explanation for the given code:

  • Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:

                    double[] myList = {1, 5, 5, 5, 5, 1};

  • Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).

                 double max = myList[0];  

  • A variable indexOfMax having datatype int will be initiated as 0.

                 int indexOfMax = 0;

  • Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.

                    for (int i = 1; i < myList.length; i++)

                            { if (myList[i] >= max)

                               { max = myList[i];

  • Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).

                  indexOfMax = i; }}

  • At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.

              System.out.println(indexOfMax);

i hope it will help you!

7 0
3 years ago
A. Calculate the diffusion coefficient for magnesium in aluminum at 450°C.
SIZIF [17.4K]

Answer:

a) D = 4.88 * 10^(-14) m^2 / s

b)   <em>t </em>= 1.1 hr

Solution:

a) Magnesium in Aluminum diffusion:

D = Do * exp(-Qd / RT)

  =  (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)

  = 4.88 * 10^(-14) m^2 / s

D = 4.88 * 10^(-14) m^2 / s

b) The composition remains same at say the distance Xo:

(Cx - Co) / (Cs - Co) = Constant

Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15

D_{550} * <em>t </em>= D_{450} * 15

(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>

(4.88 * 10^(-14) m^2 / s) * 15

by, solving for <em>t </em>we get:

 <em>t </em>= 1.1 hr

So, the time required is 1.1 hr.

5 0
3 years ago
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