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Law Incorporation [45]
3 years ago
14

Please help and show work ​

Mathematics
1 answer:
san4es73 [151]3 years ago
8 0

Step-by-step explanation:

Since PT = 2PM and AR = 2AD,

The midsegment MD must be the average of PA and TR:

Therefore we have

2(20x + 4) = 10 + (34x + 16)

=> 40x + 8 = 34x + 26

=> 6x = 18

=> x = 3

Hence length of MD

= 40(3) + 8 = 128.

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a lighthouse casts a 128 footshadow a nearby lampost that measures 5 feet 3inches cast an 8 Foot Shadow
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the area of a trapezoid is 780 cm squared. the shorter base is 48 cm and the height is 15 cm. Find the length of the other base
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6 0
3 years ago
If the geometric mean of a and 34 is 6 sqrt(17) find the value of a
Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, (n_1, n_2, ..., n_n), is given by:

G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

  • Two elements(n = 2), a and 34.
  • G = 6\sqrt{17}

Thus:

\sqrt{34a} = 6\sqrt{17}

We find the square of each side, so:

(\sqrt{34a})^2 = (6\sqrt{17})^2

34a = 36\times17

Simplifying both sides by 17:

2a = 36

a = \frac{36}{2}

a = 18

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0
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