Question

The center of a circle represented by the equation (x − 5)2 + (y + 6)2 = 42 is

Answer 1

we know that

The center-radius form of the circle equation is in the format

$(x-h)^{2} +(y-k)^{2} =r^{2}$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem

we have

$(x -5)^{2} + (y + 6)^{2} = 4^{2}$

where

the center (h,k) is the point $(5,-6)$ and the radius is equal to $4$ units

therefore

the answer is

The center of the circle is the point $(5,-6)$

Answer 2

Center = (5, -6)
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