Answer:
a. 49.5 and 54.5
Step-by-step explanation:
Class interval is a range of a value that is used to group data into equal size for easy analysis and representation of the data. It is applicable in the divisions of a histogram or bar chart into classes. Examples of class interval are 50-54, 55-59, 60-64, 65-69, 70-74 etc.
Class limit is the minimum and maximum value the class interval may contain. The minimum value is called the lower class limit and the maximum value is called the upper class limit. For class interval 50-54, the lower class limit is 50 and the upper class limit is 54.
Class boundaries are the numbers used to separate classes. It is the real limits of a class. For non-overlapping classes, the lower class boundary of each class is calculated by subtracting 0.5 from the lower class limit. The upper class boundary of each class is calculated by adding 0.5 to the upper class limit. Example: For class interval 50-54, the lower class boundary is 49.5 and the upper class class boundary is 54.5
Considering the question given, to get the real limits of the interval 50-54, 0.5 is subtracted from the lower class limit to give 49.5. Also, 0.5 is added to the upper class limit to give 54.5.
Therefore, the decimal equivalent to the expression 
is 50.02
The given expression is:
Note that 
The expression therefore becomes:
(5 x 10) + (2 x 0.01)
50 + 0.02
= 50.02
Therefore, the decimal equivalent to the expression is 50.02
Learn more here: brainly.com/question/18770964
Answer:
Step-by-step explanation:
The surface area of the square prism is obtained by using the following formula:
![A_{s} (t) = 4\cdot l(t)\cdot h(t) + 2\cdot [l(t)]^{2}](https://tex.z-dn.net/?f=A_%7Bs%7D%20%28t%29%20%3D%204%5Ccdot%20l%28t%29%5Ccdot%20h%28t%29%20%2B%202%5Ccdot%20%5Bl%28t%29%5D%5E%7B2%7D)
The rate of change of the surface area can be found by deriving the function with respect to time:
![\frac{dA_{s}}{dt} = 4\cdot [h(t)\cdot \frac{dl}{dt} + l(t)\cdot \frac{dh}{dt}] + 2\cdot l(t)\cdot \frac{dl}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA_%7Bs%7D%7D%7Bdt%7D%20%3D%204%5Ccdot%20%5Bh%28t%29%5Ccdot%20%5Cfrac%7Bdl%7D%7Bdt%7D%20%2B%20l%28t%29%5Ccdot%20%5Cfrac%7Bdh%7D%7Bdt%7D%5D%20%2B%202%5Ccdot%20l%28t%29%5Ccdot%20%5Cfrac%7Bdl%7D%7Bdt%7D)
Known variables are summarized below:
The rate of change is:
![\frac{dA_{s}}{dt} = 4\cdot [(9\,km)\cdot (-7\,\frac{km}{min} )+(4\,km)\cdot (10\,\frac{km}{min} )] + 2\cdot (4\,km)\cdot (-7\,\frac{km}{min} )](https://tex.z-dn.net/?f=%5Cfrac%7BdA_%7Bs%7D%7D%7Bdt%7D%20%3D%204%5Ccdot%20%5B%289%5C%2Ckm%29%5Ccdot%20%28-7%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29%2B%284%5C%2Ckm%29%5Ccdot%20%2810%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29%5D%20%2B%202%5Ccdot%20%284%5C%2Ckm%29%5Ccdot%20%28-7%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29)
Answer:
d is the correct answer to this question
B
B
D
A
Explanation, I have a 128% in math rn…
