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3 years ago

8

What is 15 minutes before 4:35? what time would that be? pls answer today!!!

2 answers:

ahrayia [7]3 years ago

8 0

Answer:

4:20

Step-by-step explanation:

Andrews [41]3 years ago

7 0

Answer:

4:20

Step-by-step explanation:

35-15= 20

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Given that a fair coin is tossed 3 times and X denotes the number of heads in each outcome. what is P (X=3)?

Nadusha1986 [10]

Answer:

b

Step-by-step explanation:

5 0

3 years ago

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms. What's its density in grams per cubic centimete

Ahat [919]

Answer:

The density of the bar of gold is 19.32 grams per cubic centimeter .

Step-by-step explanation:

Formula

$Density = \frac{Mass}{Volume}$

As given

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.

As 1 kilogram = 1000 gram

Than convert 13.949 kilograms into grams.

13.949 kilograms = 13.949 × 1000 grams

= 13949 grams

Mass = 13949 grams

Volume = 722 cubic centimeter

As put in the formula

$Density = \frac{13949}{722}$

Density = 19.32 grams per cubic centimeter (Approx)

Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .

8 0

3 years ago

Which expression is equivalent to m^2-13m-30?

sergiy2304 [10]

Answer: First option

Step-by-step explanation:

You have the quadratic equation given in the problem:

$m^2-13m-30$

To find an equivalent expression you cacn factorize. Find two numbers whose sum is -13 and whose product is -30.

These numbers would be -15 and 2.

Therfore, you obtain the following equivalent expression:

$(m-15)(m+2)$

If you don't want to apply the method above, you can use the quadratic formula:

$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

Where:

$a=1\\b=-13\\c=-30$

When you susbstitute values you obtain that:

$x=15\\x=-2$

Then you can rewrite the equation as $(m-15)(m+2)$

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3 years ago

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3 years ago

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago