W=y (opposite angles are equal)
z=x (opposite angles are equal)
Y= 35
Z= 55
X= 55
S= 35
U= 35
V= 55
T= 55
Total balance in Mr. Copley at the end of the month = $1473.61.
Initial deposite = $75 (not shown in his checkbook).
Let us assume his balance at the beginning of the month = x.
Total balance at the end of the month = The balance at the beginning of the month + total deposite.
$1473.61 = x + 75.
Subtracting 75 from both sides, we get
1473.61 -75 = x + 75 -75.
1398.61 = x.
Therefore, his balance at the beginning of the month was $1398.61.
Answer:
-1
Step-by-step explanation:
1.)Reorder the terms:
7(8 + x) = 49
(8 * 7 + x * 7) = 49
(56 + 7x) = 49
2.)Solving
56 + 7x = 49
3.)Solving for variable 'x'.
4.)Move all terms containing x to the left, all other terms to the right.
5.)Add '-56' to each side of the equation.
56 + -56 + 7x = 49 + -56
6.)Combine like terms: 56 + -56 = 0
0 + 7x = 49 + -56
7x = 49 + -56
7.)Combine like terms: 49 + -56 = -7
7x = -7
8.)Divide each side by '7'.
x = -1
9.)Simplifying
x = -1
Hope this helps
plz like and brainy
Answer:
1
Step-by-step explanation:
3(1)+5=8
3(0)+5=5
3(2)+5=11
3(3)+5=14
3(4)+5=17
.....
Need=51
S=12.75
G=6.5/hr•2hr=13
W=5.25/hr•5hr=26.25
S+g+w=12.75+13+26.25=52
Yes because total will be 52
......
5x+3≥23
5x≥20
x≥4
[4,8,12]
.......
9w
.....
38.88+1.87x
.....
9x-3
....
x=56
...
69=18+19+t
69=37+t
32=t
...
77-20.1-10.39=s
...
2
....
11 doesn't have an equation to solve.
...
12 doesn't have a solution to solve.
....
n≤7
...
32≤14+m
18≤m
....
120≤20+m
100≤m
...
d=50t
...
Y=5.5x
....
Y=4x
...
Dependent variable is distance.
Answer:
6x -5y = 6
Step-by-step explanation:
You can use the 2-point form of the equation of a line to find it.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (6-0)/(6-1)(x -1) +0
y = 6/5(x -1) . . . . . . point-slope form
y = (6/5)x -6/5 . . . . slope-intercept form
5y = 6x -6
6x -5y = 6 . . . . . . . standard form
