Answer:
0.22m
Step-by-step explanation:
0.22361m
Answer:
a. 
u1≤u2
b P<0.05 rejected H
Step-by-step explanation:
College High School
485 442
534 580
650 479
554 486
550 528
572 524
497 492
592 478
487 425
533 485
526 390
410 535
515
578
448
469
The mean is the average . the sum of number over the number of observation
x1=525
x2=487
s.d1=59.42
s.d2=51.74
n1=16
n2=12
Determine the hypothesis
u1≤u2
find the degree of freedom
25
p-value is the probability of obtaining the value of the test statistics. In the column of t-value in the row df=25
0.025<P<0.05
if the P value is actually less than or the same as the significant level, then the null hypothesis is rejected
P<0.05 rejected H
Answer:
42
Step-by-step explanation:
The difference in ratio units is 1, which corresponds to a difference in fruit count of 6. So the total of 7 ratio units must represent 7×6 = 42 pieces of fruit.
Answer:
Answer attached
Step-by-step explanation:
Answer:
Rs 75,000
Step-by-step explanation:
Let the total value of property be x
If one-fifth of that is given to son
property with son = 1/5 of total value of property = 1/5 of x = x/5
If one-third of that is given to daughter
property with daughter = 1/3 of total value of property = 1/3 of x = x/3
remaining property after giving the portions to son and daughter
= total value of property - property with son -property with daughter
= x - x/5 - x/3
taking LCM of 5 and 3 (15)
= (15x - 3x - 5x)/15
= 7x/15
Given that remaining property was given to wife
property with wife = 7x/15
it is given that wife got 35000 Rs
thus,
7x/15 = 35,000
7x = 35,000*15 = 525,000
x = 525,000/7 = 75,000
Thus, total worth of property =Rs 75,000 Answer
